1.5x^2+3x-13.5=0

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Solution for 1.5x^2+3x-13.5=0 equation:



1.5x^2+3x-13.5=0
a = 1.5; b = 3; c = -13.5;
Δ = b2-4ac
Δ = 32-4·1.5·(-13.5)
Δ = 90
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{90}=\sqrt{9*10}=\sqrt{9}*\sqrt{10}=3\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{10}}{2*1.5}=\frac{-3-3\sqrt{10}}{3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{10}}{2*1.5}=\frac{-3+3\sqrt{10}}{3} $

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